(2+y)(2y^2+2y+2)=

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Solution for (2+y)(2y^2+2y+2)= equation: 


Simplifying
(2 + y)(2y2 + 2y + 2) = 0

Reorder the terms:
(2 + y)(2 + 2y + 2y2) = 0

Multiply (2 + y) * (2 + 2y + 2y2)
(2(2 + 2y + 2y2) + y(2 + 2y + 2y2)) = 0
((2 * 2 + 2y * 2 + 2y2 * 2) + y(2 + 2y + 2y2)) = 0
((4 + 4y + 4y2) + y(2 + 2y + 2y2)) = 0
(4 + 4y + 4y2 + (2 * y + 2y * y + 2y2 * y)) = 0
(4 + 4y + 4y2 + (2y + 2y2 + 2y3)) = 0

Reorder the terms:
(4 + 4y + 2y + 4y2 + 2y2 + 2y3) = 0

Combine like terms: 4y + 2y = 6y
(4 + 6y + 4y2 + 2y2 + 2y3) = 0

Combine like terms: 4y2 + 2y2 = 6y2
(4 + 6y + 6y2 + 2y3) = 0

Solving
4 + 6y + 6y2 + 2y3 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), '2'.
2(2 + 3y + 3y2 + y3) = 0

Ignore the factor 2.

Subproblem 1
Set the factor '(2 + 3y + 3y2 + y3)' equal to zero and attempt to solve:

Simplifying
2 + 3y + 3y2 + y3 = 0

Solving
2 + 3y + 3y2 + y3 = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

The solution to this equation could not be determined.

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